pq(p^2-q^2)=pq(p-q)(p+q)=(p^2-pq)(pq+q^2)x^2-(p^2+q^2)x+(p^2-pq)(pq+q^2)=0[x-(p^2-pq)][x-(pq+q^2)]=0x=p^2-pq或pq+q^2
我刚上高一，对不起了，帮不了你，不好意思哟
